15-02-2014, 11:45
(15-02-2014 02:20)Julita escribió: [ -> ](12-02-2014 17:19)Polito! escribió: [ -> ]\[\oint_{C^+}f.dg=\int \int _{\Sigma }(Rotf.\bar{n})d\Sigma \]
\[\int \int _{\Sigma }(Rotf.\bar{n})d\Sigma = \int \int 1+x dxdz=\int_{0}^{2\pi}d\theta\int_{0}^{2}\rho+\rho ^{2}\cos \theta d\rho\]
\[\int_{0}^{2\pi }\left [ \frac{\rho^{2}}{2}+cos\theta *\frac{\rho ^{3}}{3} \right ]_{0}^{2}d\theta \]
\[\int_{0}^{2\pi }\left (2+cos\theta *\frac{8}{3} \right )d\theta \]
\[\left [2\theta+sen\theta *\frac{8}{3} \right ]^{2\pi }_{0}\]
\[\Phi =4\pi\]
Gracias, fue un calculo mental que hice mal..